lower bound: | 72 |
upper bound: | 74 |
Construction of a linear code [95,5,72] over GF(5): [1]: [95, 5, 72] Linear Code over GF(5) code found by Axel Kohnert Construction from a stored generator matrix: [ 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 2, 1, 1, 1, 3, 4, 3, 2, 2, 3, 2, 4, 1, 3, 1, 3, 1, 2, 1, 4, 3, 2, 2, 4, 3, 2, 3, 3, 4, 2, 4, 1, 3, 1, 2, 1, 4, 1, 0, 4, 4, 0, 0, 1, 0, 1, 2, 2, 4, 2, 3, 2, 3, 3, 0, 4, 1, 1, 2, 2, 0, 4, 0, 3, 0, 2, 3, 1, 3, 2, 0, 0, 3, 2, 1, 0, 1, 3, 0, 2, 0, 0, 0, 3, 0 ] [ 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 2, 1, 1, 3, 2, 3, 3, 2, 3, 4, 1, 4, 1, 2, 2, 3, 1, 2, 3, 4, 2, 1, 3, 4, 3, 4, 2, 4, 1, 3, 2, 1, 3, 2, 4, 1, 0, 4, 4, 0, 1, 4, 0, 0, 3, 4, 1, 3, 3, 1, 4, 3, 2, 2, 2, 3, 0, 0, 0, 1, 0, 4, 3, 2, 1, 3, 2, 3, 0, 2, 1, 0, 1, 2, 2, 0, 0, 3, 0, 0, 1, 0, 0, 3 ] [ 0, 0, 1, 0, 0, 1, 1, 0, 1, 1, 1, 1, 2, 1, 3, 2, 2, 3, 4, 1, 1, 2, 2, 3, 4, 1, 2, 3, 3, 4, 4, 1, 2, 3, 3, 2, 3, 1, 2, 3, 1, 2, 4, 3, 4, 1, 0, 4, 4, 0, 1, 4, 0, 0, 4, 2, 2, 3, 3, 1, 2, 2, 4, 0, 3, 0, 0, 3, 4, 1, 2, 3, 3, 0, 2, 1, 1, 0, 0, 1, 1, 2, 3, 0, 0, 1, 2, 3, 3, 0, 2, 0, 1, 0, 0 ] [ 0, 0, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 2, 3, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 0, 1, 1, 1, 0, 0, 0, 1, 4, 4, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 3 ] [ 0, 0, 0, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 ] last modified: 2006-03-27
Lb(95,5) = 72 Koh Ub(95,5) = 74 follows by a one-step Griesmer bound from: Ub(20,4) = 14 is found by considering shortening to: Ub(19,3) = 14 is found by considering truncation to: Ub(17,3) = 12 Hi4
Koh: Axel Kohnert, email, 2006.
Notes
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